What is the integral of 1 x? - Mathematics Stack Exchange $\begingroup$ "Answers to the question of the integral of 1x are all based on an implicit assumption that the upper and lower limits of the integral are both positive real numbers" --- not completely correct: if they are both negative it also works This is an improper integral and does not converge in the remaining cases $\endgroup$ –
What is the integral of - Mathematics Stack Exchange This integral is one I can't solve I have been trying to do it for the last two days, but can't get success I can't do it by parts because the new integral thus formed will be even more difficult to solve I can't find out any substitution that I can make in this integral to make it simpler Please help me solve it
Newest integration Questions - Mathematics Stack Exchange For questions about the properties of integrals Use in conjunction with (indefinite-integral), (definite-integral), (improper-integrals) or another tag(s) that describe the type of integral being considered This tag often goes along with the (calculus) tag
calculus - Is there really no way to integrate $e^{-x^2 . . . $\begingroup$ @user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, move the dummy copy into the first integral to get a double integral